![]() ![]() You have just to store that value and your user will be identified at the next launch of your application. UUID.randomUUID() method generates an unique identifier for a specific installation. String uniqueID = UUID.randomUUID().toString() Only 2.2 has the problems.Īs the requirement for most of applications is to identify a particular installation and not a physical device, a good solution to get unique id for an user if to use UUID class. ANDROID_ID is perfectly reliable on versions of Android =2.3. There is also a known bug with a popular handset from a manufacturer where every instance have the same ANDROID_ID.īe aware that ANDROID_ID could be changed after user switch (multiuser in 4.2).īut, accordingly to ANDROID_ID is the preferred device identifier. However, the value may change if a factory reset is performed on the device. String androidId = (getContentResolver(), _ID) To retrieve the value, you can use the following code: ANDROID_ID seems a good choice for a unique device identifier because it’s available for smartphones and tablets. It’s a 64-bit number that should remain constant for the lifetime of a device. ![]() On a device first boot, a randomly value is generated and stored. There are several solutions and we going to examine them all. Sometimes it is required to get the unique ID of android device (phone, tablet, tv, wear) while developing the android application. Uuid generator android bluetooth how to#How to get Unique ID to identify Android devices Android ![]()
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